Question

If one of the zeroes of the quadratic polynomial 6x^2-kx+2(k+1) is 1 then find the value of k.

Answer 1

Step-by-step explanation:

Hope it helps you in your learning process.

Answer 2

Answer:

since one of its zeroes is 1.

so substitute x = 1.

6×1^2 - k×1 + 2 (k+1)= 0

=> 6 - k + 2k + 2= 0

=> 8 + k = 0

=> k = -8

hope it helps dear....❤❤