If one of the zeroes of the quadratic polynomial (k-1)x^2+1 is -3
Answers
Answered by
0
Answer:
Step-by-step explanation:
(k - 1)x² + kx + 1.
Since one of the zeroes is -3,so when we substitute -3 in the polynomial we get 0
(k - 1) (-3)² + k (-3) + 1 = 0
=> 9k - 9 - 3k + 1 = 0
=> 6k - 8 = 0
=> 6k = 8
=> k = 8/6 = 4/3
Thus the value of k = 4/3.
Similar questions