Question

If one of the zeroes of the quadratic polynomial (k-1)x^2+kx+1 is -3, then the value of k is

a. 4/3
b. -4/3
c. 2/3
d. -2/3

Please explain the procedure also

Answer 1

$\huge \bold \pink{heya}$

One of the zeroes of the polynomial is -3,

so f(-3)=(k-1)(-3)²+k(-3)+1

f(-3)=(k-1)9-3k+1

f(-3)=9k-9-3k+1

f(-3)=6k-8

6k=8

k=8/6

k=4/3

Answer:

Option A

Answer 2

Answer:

k=4/3

Step-by-step explanation:

Since -3 is one of the zeroes of the given quadratic polynomial

(k-1)(-3)^2+k(-3)+1=0

(k-1)9-3k+1=0

9k-9-3k+1=0

6k-8=0

6k=8

k=4/3