If one of the zeroes of the quadratic polynomial (k-1)x++ box + 1 is -3, then what is the 1
value of k?
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Answer:
4/3
Step-by-step explanation:
As -3 is one of the zeros of quadratic polynomial (k-1) x^2+Kx+1
= When we substitute -3 in the polynomial, we get 0
= (k-1) (-3)^2 + k (-3)+1=0
= 9k-9-3k+1=0
= 6k-8=0
k= 8/6= 4/3
Hope you will understand
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