Question

If one of the zeroes of the quadratic polynomial (k–1) x2 + k x + 1 is –3, then thevalue of k is

Answer 1

Step-by-step explanation:

$= > (k - 1)(9) - 3k + 1 = 0 \\ = > 9k - 9 - 3k + 1 = 0 \\ = > 6k - 8 = 0 \\ = > 6k = 8 \\ = > k = \frac{8}{6} \\ = > k = \frac{4}{3}$