Question

If one of the zeroes of the quadratic polynomial (k-1)x2

+ kx +1 is -3, then the value of k is

(a) (b) - (c) (d)-​

Answer 1

hey buddy

here is your ans..

Answer:

K = 4/3 = 1.3333333

Step-by-step explanation:

$(k - 1) {x}^{2} + kx + 1 \\ \\ one \: zero \: is \: given \: i.e \: = - 3 \\ put \: ( - 3) \: in \: the \: place \: of \: x \\ \\ (k - 1)( - 3) {}^{2} + k( - 3) + 1 = 0 \\ (k - 1)(9) - 3k + 1 = 0 \\ 9k - 9 - 3k + 1 = 0 \\ 9k - 3k - 9 + 1 = 0 \\ 6k - 8 =0 \\ k = \frac{8}{6} = \frac{4}{3} = 1.33333333$

I hope it helps you

thank you

good night

Answer 2

k = 1.33333

Hope it helps..........