If one of the zeroes of the quadratic polynomial (k-1) x²+kx+1is -3.,then find the value of k
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Answered by
5
k = 4/3
Try it by putting the value of x in the equation.....good luck !!!!
Try it by putting the value of x in the equation.....good luck !!!!
Answered by
8
Given Equation is f(x) = (k - 1)x^2 + kx + 1
Given that one zero of the zeroes of the equation is -3.
f(-3) = 0.
(k - 1)(-3)^2 + k(-3) + 1 = 0
(k - 1)(9) - 3k + 1 = 0
9k - 9 - 3k + 1 = 0
6k - 8 = 0
6k = 8
k = 8/6
k = 4/3.
Therefore the value of k = 4/3.
Hope this helps!
Given that one zero of the zeroes of the equation is -3.
f(-3) = 0.
(k - 1)(-3)^2 + k(-3) + 1 = 0
(k - 1)(9) - 3k + 1 = 0
9k - 9 - 3k + 1 = 0
6k - 8 = 0
6k = 8
k = 8/6
k = 4/3.
Therefore the value of k = 4/3.
Hope this helps!
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