if one of the zeroes polynomial p(x):x²-8x+k is seven times of other find value of k
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if one zero is x then other zero is 7x
so x+7x=8
8x=8
then x=1
since product of roots is k
x*7x=k
7x^2=k. (k=1)
k=7
so x+7x=8
8x=8
then x=1
since product of roots is k
x*7x=k
7x^2=k. (k=1)
k=7
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