if one of the zeros of (a^4+4)x²+13x+4a find a
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Now let one of the roots be A. Then according to question the other root must be 1/A.
Now we know that
Product of roots = constant term of quadratic equation/(coefficient of x²)
Putting values we get
A x 1/A = 4a/(a² + 4) = 1 = 4a/(a² + 4)
= a² + 4 = 4a = a² - 4a + 4 = 0 ( rearranging above equation)
= a² - 2a - 2a + 4 = 0 = a(a - 2) - 2(a - 2) = 0
= (a - 2)(a - 2) = 0 = (a - 2)² =0
= a - 2 = 0 = a = 2
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