Question

If one of the zeros of a cubic polynomial is X3+px^2+r is -1​

Answer 1

Answer:

-1 no need to mark as brainlist if ya don't want to

Step-by-step explanation:

= -1 should be the answer hope it helps

Answer 2

Answer:

$Here \: x = - 1$

${x}^{3} + p {x}^{2} + r = 0$

${( - 1)}^{3} + p {( -1 )}^{2} + r = 0$

$- 1 + p + r = 0$

$p + r = 1$