If one of the zeros of p(x) = (k-1)x²+kx+1 is -3 find k
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Answer:
k=4/3
Step-by-step explanation:
Putting value of x as -3
⇒ (k-1)9 + (-3)k + 1 = 0
⇒ 9k-9-3k+1=0
⇒ 6k=8
⇒ k=8/6
⇒ ∴ k=4/3
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