Question

if one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3then find the value of k

Answer 1

hi friend,

given one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3

so when we substitute -3 in the polynomial ,we get 0

→(k-1)(-3)²+k(-3)+1=0

→9k-9-3k+1=0

→6k-8=0

→k=8/6=4/3


I hope this will help u ;)

Answer 2

Hi there !

Zero of the polynomial = -3

p(-3) = (k-1) x (-3)²+k x -3 +1 =0

( k -1)9 -3k + 1 = 0

9k - 9 - 3k + 1 =0

6k - 8 =0

6k = 8

k = 8/6

= 4/3