Question

If one of the zeros of the polynomial (k -1) x² +kx +1 is 13 the find the value of k​

Answer 1

Answer:

k=84/91

Step-by-step explanation:

f(x)= (k-1)$x^{2}$ + kx + 1

f(13)= (k-1)$13^{2}$ + 13k +1 = 0

     = 169k-169+13k+1=0

        182k=168

        k=168/182

          =84/91