Question

if one of the zeros of the polynomial P of x is equal to x square - X + K is 2 then the value of k is ​

Answer 1

answer:

p(x)=x²-x+k

zero is 2

g(x)=x-2

since g(x) is a zero of p(x)

p(2)=0

(2)²-2+k=0

4-2+k=0

2+k=0

k=-2

Answer 2

The value of k is equal to - 2.

Step-by-step explanation:

The given polynomial

P(x) = $x^2$ - x + 2

2 is one of the zeros of polynomial P(x).

To find, the value of k = ?

∴ P(x) = 0

Put x = 2 in P(x), we get

$2^2$ - 2 + k = 0

⇒ 4 - 2 + k = 0

⇒ 2 + k = 0

⇒ k = - 2

∴ The value of k = - 2

Thus, the value of k is equal to - 2.