if one of the zeros of the quadratic polynomial (k-1)x*x+kx+1 is (-3), then the value of k is?
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Answer:
K=4/3
Step-by-step explanation:
Given that, one of the zeroes of the quadratic polynomial say p(x) = (k- 1)x2 + kx + 1 is -3,then p(-3) = 0
⇒ (k-1)(-3)2 + k(-3) + 1 = 0
⇒ 9(k-1)-3k + 1 = 0
⇒ 9k - 9 - 3k + 1 = 0
⇒ 6k - 8 = 0
∴ k = 4/3
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it is a very simple question for a student of class 0
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