Question

if one of the zeros of the quadratic polynomial (k-1)x2+kx+1 is -3 then value of k is
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Answer 1

Answer:

k = 4/3

Step-by-step explanation:

substituting value ox = -3 in the equation ,

9k - 9 - 3k + 1 = 0

9k - 3k - 8 = 0

therefore ,

6k = 8

k = 8/6 = 4/3

hope it helps!!!

Answer 2

$f(x) = (k - 1)x² + kx + 1$

$f(3) = 0$

$(k - 1) × (3)² + (-3)k + 1 = 0$

$(k - 1)9 - 3k + 1 = 0$

$9k - 9 - 3k + 1 = 0$

$6k - 8 = 0$

$6k = 8$

$k = \frac{8}{6}$

$k = \frac{4}{3}$