if one of thw roots of quadratic equation kxsquare-7x+12=0 is 3 find k
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Question :
if one of the roots of quadratic equation kx²-7x+12=0 is 3 find k
Answer :
k = 1
Given :
- quadratic equation, kx²-7x+12 = 0
- 3 is one of the roots.
To find :
the value of k
Solution :
Given quadratic equation,
kx²-7x+12 = 0
Let p(x) = kx²-7x+12
Since 3 is one of the roots of the given quadratic equation,
=> p(3) = 0
When we substitute the value of x = 3, we get 0
Put x = 3,
k(3)² - 7(3) + 12 = 0
k(9) - 21 + 12 = 0
9k - 9 = 0
9k = 9
k = 9/9
k = 1
∴ The value of k is 1.
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