integration of 3x+1/2x²+3x+1
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Answer:
=∫
2x
2
+x+1
3x+1
dx
=
4
3
∫
2x
2
+x+1
4x+1
dx+
4
1
∫
2x
2
+x+1
dx
Substitute 2x
2
+x+1=t for first
∴(4x+1)dx=dt
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