Question

if one rooneot of the equation 4x^2-8kx-9=0 is negative of the other, then find the value of k

Answer 1

Answer:

k=0

Explanation:

given that one root is negative to the other

therefore if one root is (a)

then another would be -(a)

Here a=4 ,b=-8k , c=-9

Sum of zeros =-b/a

a+(-a)= -(-8k)/4

0=2k

0/2=k

0=k ANSWER

Answer 2

Explanation:

Answer :- ---

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.