Question

If one root is square then other root so find the value of p=? in this equation : x^2 - 30x + p =0​

Answer 1

let one root be t then other root is t^2

according to question

(X - t)(X - t^2) = 0

x^2- xt - xt^2 +t^3 = 0

X^2 - X(t +t^2) + t^3= 0

So

Coffecient of X is 30

t + t^2 -30 = 0

t^2 + 6t -5t -30 =0

t(t+6) -5(t +6)= 0

t = -6 and 5

Now

p = t^3

p = 125 or -216