Two pillars of height 8 feet each with four faces shown, of the gate of a stadium have one-one pyramid of height 4 feet each having same base of their tops. The base of each pillar is 6ft * 6ft. If the pillars with pyramid are painted with Rs. 90 per square feet, what will be the total cost?
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Step-by-step explanation:
Pillar dimension = 6 * 6 * 8 ft (
one Piler 4 faces area = 4 * 6 * 8 = 192 ft²
two piller area = 2 * 192 = 384 ft²
one pyramid area = 6 * √( (6/2)² + 4²) + 6 * √( (6/2)² + 4²) ( 6 * 6 area of pyramid will not be painted as it is hidden)
= 6 * 2 * 5
= 60 ft²
two pyramid area = 2 * 60 = 120 ft²
Total area to be painted = 384 + 120 = 504 ft²
Total cost = 75 * 504 = Rs 37800
hope it helps you mark as brainliest please
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