If one root of 2x
2 + 13x+k = 0 is reciprocals of the other, then k is a) 2 b) 5 c) 1
6
d) 6
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Answer:
Let one root of the given that other zero is Reciprocal the one zero.
So,
Other zero=1/Alpa.
Given polynomial is 5x
2
+13x+k=0.
Here,
A=coefficient of x
2
B=coefficient of x
And,C=constant term.
Product of zeroes =C/A
Alpha ×1/Alpha =K/5
1=K/5
K=5
Then,
We get k=5.
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