Question

If one root of 2x2 + kx-6=0 is 2 then find
k value.​

Answer 1

Answer:

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2 is zero of this p(x)=2x²+kx-6=0

so, put value of x=2

p(x)=2x²+kx-6=0

p(2)=2(2)²+k(2)-6=0

=> 8+2k-6=0

=> 2+2k=0

=> 2k=-2

=> k=-1

hope it helps you....✌✌☺️