Question

if one root of 5 x square + 13 x + K is reciprocal of the Other root then find the value of k

Answer 1

The given equation

5x^2 + 13 x + k = 0

Now let's consider one root as t
So the other will be 1/t according the given condition.

So, the product of roots = t*1/t = 1
Now,
Product of roots = Coefficient in constant term / Coefficient of x^2 = k/5

Now,
k/5 = 1
Therefore,
k=5

Answer 2

Answer:

Hiii friend,

Let Alpha be the one zero of the given polynomial.

Then the other will be 1/Alpha

P(X) = 5X²+13X+K

Here,

A = 5 , B = 13 and C= K

Product of zeros = C/A

Alpha × 1/Alpha = K/5

1 = K/5

K = 5.