Question

If one root of 5x² + 13x + k =0
is the reciprocal of the of the other root then Find the value of K.​

Answer 1

ANSWER

ANSWERLet one root of the given that other zero is Reciprocal the one zero.

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2 B=coefficient of x

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2 B=coefficient of xAnd,C=constant term.

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2 B=coefficient of xAnd,C=constant term.Product of zeroes =C/A

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2 B=coefficient of xAnd,C=constant term.Product of zeroes =C/AAlpha ×1/Alpha =K/5

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2 B=coefficient of xAnd,C=constant term.Product of zeroes =C/AAlpha ×1/Alpha =K/51=K/5

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2 B=coefficient of xAnd,C=constant term.Product of zeroes =C/AAlpha ×1/Alpha =K/51=K/5K=5

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2 B=coefficient of xAnd,C=constant term.Product of zeroes =C/AAlpha ×1/Alpha =K/51=K/5K=5Then,

ANSWERLet one root of the given that other zero is Reciprocal the one zero.So,Other zero=1/Alpa.Given polynomial is 5x 2 +13x+k=0.Here,A=coefficient of x 2 B=coefficient of xAnd,C=constant term.Product of zeroes =C/AAlpha ×1/Alpha =K/51=K/5K=5Then,We get k=5.

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Answer 2

Answer :

• K = 5

S O L U T I O N :

Given,

• Quadratic polynomial, 5x² + 13x + k = 0.

• One roots is the reciprocal of the other root.

To Find,

• Value of k.

Explanation,

Given, Quadratic polynomial, 5x² + 13x + k = 0.

On comparing with, ax² + bx + c = 0, We get;

=> a = 5 , b = 13 , c = k

Given, One roots is the reciprocal of the other root.

=> One root = α

=> Other root = 1/α

We know that,

Product of roots = c/a

[ Put the values ]

=> α × 1/α = k/5

=> 1 = k/5

=> k = 5

Therefore,

The value of k is 5.