if one root of a quadratic equation 6 x raise to power 2 - x - k = zero is 2/3 find the value of k
Answers
Answered by
7
Heya !!
6x² - x - k
Here,
a = 6 , B = -1 and C = -k.
Sum of zeroes = -b/a
2/3 + other zero = -(-1)/6
other zero = 1/6 - 2/3
Other zero = ( 1 - 4 ) /6 = -3/6 = -1/2
And,
Product of zeroes = C/A
2/3 × -1/2 = -k/6
-6k = 12
K = -2
6x² - x - k
Here,
a = 6 , B = -1 and C = -k.
Sum of zeroes = -b/a
2/3 + other zero = -(-1)/6
other zero = 1/6 - 2/3
Other zero = ( 1 - 4 ) /6 = -3/6 = -1/2
And,
Product of zeroes = C/A
2/3 × -1/2 = -k/6
-6k = 12
K = -2
Similar questions