if one root of equation 2xsq- 8x-m =0is 3/2 find the other root of quadratic equation
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Solution :
Given Quadratic equation
2x² - 8x - m = 0 .
It is given that , 3/2 one root of the
equation .
substitute x = 3/2 in the equation, we
get
2(3/2)² - 8(3/2) - m = 0
=> 9/2 - 24/2 - m = 0
=> ( 9 - 24 )/2 - m = 0
=> -15/2 = m
Therefore ,
m = -15/2
Now ,
Equation becomes ,
2x² - 8x + 15/2 = 0 Compare this
with ax² + bx + c = 0 , we get
a = 2 , b = -8 , c = 15/2
Let the second root = p
first root = 3/2
product of the roots = c/a
=> ( 3/2 ) × p = ( 15/2 )/2
=> p = ( 15 × 2 )/( 2 × 2 × 3 )
=> p = 5/2
Therefore ,
Second root ( p ) = 5/2
•••••
Given Quadratic equation
2x² - 8x - m = 0 .
It is given that , 3/2 one root of the
equation .
substitute x = 3/2 in the equation, we
get
2(3/2)² - 8(3/2) - m = 0
=> 9/2 - 24/2 - m = 0
=> ( 9 - 24 )/2 - m = 0
=> -15/2 = m
Therefore ,
m = -15/2
Now ,
Equation becomes ,
2x² - 8x + 15/2 = 0 Compare this
with ax² + bx + c = 0 , we get
a = 2 , b = -8 , c = 15/2
Let the second root = p
first root = 3/2
product of the roots = c/a
=> ( 3/2 ) × p = ( 15/2 )/2
=> p = ( 15 × 2 )/( 2 × 2 × 3 )
=> p = 5/2
Therefore ,
Second root ( p ) = 5/2
•••••
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