Question

If one root of equation is x2

– kx + 12 = 0 is 3, then find k.......plss ans this question​

Answer 1

Step-by-step explanation:

x =  3

now,

x² - kx + 12 = 0

3² - k*3 + 12 = 0

9 - 3k +12 = 0

-3k + 21 = 0

3k = 21

k=7

Answer 2

step-by-step explanation

x2-kx+12=0

(3)2-k(3)+12=0

9-3k+12=0

21-3k=0

-3k = 0-21

-3k= -21

3k= 21

k=7..

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