Question

if one root of equation (x+4)(x+3)=0 is -4 then find the other root of equation​

Answer 1

Answer:

Other root of the equation is -3

Explanation:

Given polynomial,

⇒ (x + 4)(x + 3) = 0

⇒ x² + 7x + 12 = 0

Let α be the one root and β another root.

On comparing the given polynomial with the general form of equation ax² + bx + c

• a = 1
• b = 7
• c = 12

Now, product of the roots,

⇒ α*β = c/a

Substituting the values,

⇒ -4*β = 12/1

⇒ -4*β = 12

⇒ β = 12/-4

⇒ β = -3

Hence, the other root of the equation is -3.

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• General form of a quadratic equation :- ax² + bx + c Where, a, b, & c are constant
• Sum of zeros :- -b/a
• Product of zeros = c/a