if one root of quadratic equation is 3-4i where a,b,c, belongs to r then a+b+c=
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Other root is 3+4i
Now sum of rots is - b/a
So 6=-b/a
b=-6a
And 9+4=c/a
So c=13a
Now a+b+c=20a
Now sum of rots is - b/a
So 6=-b/a
b=-6a
And 9+4=c/a
So c=13a
Now a+b+c=20a
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