Question

If one root of quadratic equation p^2-3p+k is 5 find k

Answer 1

Step-by-step explanation:

$(5) {}^{2} - 3(5) + k = 0$

$25 - 15 + k = 0$

$k = - 10$

Answer 2

let f(p)=p^2-3p+k .........(1)

given, the root is 5

now,f(p)=0

putting, p=5

f(5)=5^2-3×5+k=0

25-15+k=0

10+k=0

k=-10

Hope it helps you mate.

Thanks .