If one root of the equation x^2+px-12=0 is 4 and the roots of x^2-2px+q=0 are equal, then value of q is
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3
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Answered by
1
Answer:
p = - 1.
Step-by-step explanation:
As the roots are equal, thus the root of the equation is only 4.
Therefore,
4^2+p(4)-12=0
=> 16+4p-12=0
=> 4+4p=0
=> 4p= - 4
=> p = 4/(-4)
=> p = - 1 ......Ans.
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