If one root of the equation x^2-px+8=0 is twice the other then p=
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sum of root(a+b)=p-----------------------------1
multiple of roots ab=8----------------------2
according to question a=2b ----------------3
put the value of a in -------2
2b x b =8
2 b^2 =8
b^2=4
b=2,-2
put the value of b in ---------------3
then a= 2 x 2 =4
and a= -2 x 2= -4
hence we have a=4, b=2 and a=-2 , b=-4 put this value in -----------------1
we have 2+4 = p
so , p=6
and -2 + -4 =p
so p= -6
so the correct answer is p = -6
Step-by-step explanation:
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