if one root of the equation X square + bx + 3 is equal to zero is the square of the other than P cube + Q square is equals to
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Answer:
P³ + Q² = 9 + 9∧(1/3)
Step-by-step explanation:
x² + bx + 3 = 0
ie, PQ = 3
given P = Q ²
Q³ = 3
Q = 3∧(1/3) P = 3∧(2/3)
P³ + Q² = 3² + 3∧(2/3) = 9 + 9∧(1/3)
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