if one root of the equation x²+7x+k=0 is 2 , then find the value of k and other root ?
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The value of k= -18 and other root is -9
jaswanth790:
how did u get the roots
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x²+7x+k=0
Given one root is 2
Put x=2 in eq given:
=> (2)^2+7(2)+k=0
=> 4+14+k=0
=> k=-18
So equation will be : x^2+7x-18=0
X^2+9x-2x-18=0
=> x(x+9)-2(x+9)=0
=> (x+9)(x-2)
So other root will be (-9)
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