if one root of the equation x2+ax+3=0 is 1, then its other root is
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Let α be the one root of the equation and β be the other root .
Given : x² + ax + 3 = 0 , α = 1
On comparing the given equation with ax² + bx + c = 0
Here, a = 1 , b = a , c = 3
Product of zeroes = c/a
α × β = c/a
1× β = 3/1
β = 3
Hence, the other root of the equation is β = 3 .
Answered by
17
Answer:
Let α be the one root of the equation and β be the other root .
Given : x² + ax + 3 = 0 , α = 1
On comparing the given equation with ax² + bx + c = 0
Here, a = 1 , b = a , c = 3
Product of zeroes = c/a
α × β = c/a
1× β = 3/1
β = 3
Hence, the other root of the equation is β = 3 .
Step-by-step explanation:
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