Question

If one root of the equation x2+ax+3=0 is 1 then the other root is

Answer 1

Answer:

other root is -3

Step-by-step explanation:

1²+a(1)+3=0

1+3+a=0

a=-4

now,

$x^{2}$-4x+3

0=$x^{2}$-x-3x+3

0=x(x-1)+3(x-1)

0=(x-1)(x+3)

x=-3

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