if one root of the polynomial 5x^3+13x+k is reciprocal of the other,then find the value of k
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Given:- one root of the polynomial 5x^2+13x+k is reciprocal of the other
Let to be Required Number be a
Reciprocal of a=1/a
Product of Roots=a×1/a
Sum of Zeroes=Product of Zeroes
Product of Zeroes=c/a=k/5
According to the Question statement!
Product=Required terms
k/5=1
k=5×1
k=5
Ans:- k=5
Thanks!!!
Anonymous:
Thanks for brainliest
Answered by
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bonjour!
We know that in a quadratic equation ax^2 + bx + c = 0
Product of roots = c/a
Here we have the equation 5x^2 + 13x + k = 0
Product of roots = k/5
Given that the roots are reciprocals of each other. So if one root is p, the other would be 1/p. So, their product will always be 1.
=> 1 = k/5
=> k = 5.
Hence, the value of k is 5.
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