If one root of the quadratic eqn x^2-11x+k =0 is 9, then find value of k?
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Given equation is x²-11x+k= 9
as soln. of this equation is 9 then put x = 9 in this equation
9² -11*9 + k = 0
81 - 99 + k = 0
-18+ k = 0
k = 18
hence value of k is 18.
@_@
as soln. of this equation is 9 then put x = 9 in this equation
9² -11*9 + k = 0
81 - 99 + k = 0
-18+ k = 0
k = 18
hence value of k is 18.
@_@
Answered by
0
Answer:
Step-by-step explanation:
let the other root be y
therefore two roots will be 9 and y
as the roots sum should be equal to - b/a
therefore 9 + y= -(-11)/1
therefore y = 2
and also the product of roots is equal to c/a
therefore (9)(2) = k/1
therefore k = 18
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