Math, asked by sasmitarajhans4, 7 months ago

if one root of the quadratic equation 2x2+mx-6=0is 2, then the value of m is​

Answers

Answered by ranshi47
0

Step-by-step explanation:

Given: Since x=2 is a root of the equation

2x²+mx−6=0

∴2×2² +2m−6=0⇒8+2m−6=0⇒2m+2=0⇒m=−1

Putting m=−1 in the equation 2x²+mx−6=0,

Now to find other root of given equation

2x²−x−6=0⇒2x² −4x+3x−6=0

⇒2x(x−2)+3(x−2)=0

⇒(x−2)(2x+3)=0⇒x−2=0,2x+3=0

⇒x=2,x= -3/2

Hence the other root is = -3/2

Answered by amitnrw
1

Given : 2x²+mx-6 = 0

One root is  2

To Find: Value of the m

Solution:

2x²+mx-6 = 0

One root is  2

=> 2(2)² + m(2)  - 6 = 0

=> 8 + 2m - 6 = 0

=> 2m + 2 = 0

=> m+ 1 = 0

=> m = -1

The value of M is - 1

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