if one root of the quadratic equation 2x2+mx-6=0is 2, then the value of m is
Answers
Step-by-step explanation:
Given: Since x=2 is a root of the equation
2x²+mx−6=0
∴2×2² +2m−6=0⇒8+2m−6=0⇒2m+2=0⇒m=−1
Putting m=−1 in the equation 2x²+mx−6=0,
Now to find other root of given equation
2x²−x−6=0⇒2x² −4x+3x−6=0
⇒2x(x−2)+3(x−2)=0
⇒(x−2)(2x+3)=0⇒x−2=0,2x+3=0
⇒x=2,x= -3/2
Hence the other root is = -3/2
Given : 2x²+mx-6 = 0
One root is 2
To Find: Value of the m
Solution:
2x²+mx-6 = 0
One root is 2
=> 2(2)² + m(2) - 6 = 0
=> 8 + 2m - 6 = 0
=> 2m + 2 = 0
=> m+ 1 = 0
=> m = -1
The value of M is - 1
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