Question

if one root of the quadratic equation ax^2+bx+c=0 is triple the other show that 3b^2=16 bc

Answer 1

please mark as brainliest

Answer 2

let one root =p
second root = triple to p = 3p
1) sum of the roots =-b/a
p+3p=-b/a
4p=-b/a
square both sides
16p^2=b^2/a^2
p^2 =b^2/16a^2----(1)
2) product of the roots =c/a
p*3p= c/a
3p^2=c/a
3(b^2/16a^2)=c/a from (1)
3b^2=16a^2c/a
3b^2=16ac