If one root of the quadratic equation is 2x^2-3x+p=0 is 3 ,find the other root of the quadratic equation. Also find the value of p.
Answers
Answered by
50
Hey
Here is your answer,
Let the other zero be q.
2x^2-3x+p=0
Sum of zeroes = -b/a
3+q = 3/2
q = 3/2 - 3
q = 3-6/2
q = -3/2
Product of zeroes = c/a
3+(-3/2) = p/2
6-3/2 = p/2
3/2 = p/2
p=3
Hope it helps you!
Here is your answer,
Let the other zero be q.
2x^2-3x+p=0
Sum of zeroes = -b/a
3+q = 3/2
q = 3/2 - 3
q = 3-6/2
q = -3/2
Product of zeroes = c/a
3+(-3/2) = p/2
6-3/2 = p/2
3/2 = p/2
p=3
Hope it helps you!
Answered by
6
Given,
The quadratic equation 2x²-3x+p = 0 is given along with its one root that is 3.
To find,
The other root of the given equation and the value of p.
Solution,
The other root of the quadratic equation 2x²-3x+p = 0 is -3/2 and the value of p is -9.
We can simply find the other zero of the quadratic equation by using the sum of zeroes.
Let the other zero of the quadratic equation is 'q'
sum of zeroes = -b/a
3+q = 3/2
q = 3/2-3
q = -3/2
which is the required other root of the equation.
Product of the zero = c/a
-3/2 * 3 = p/2
p = -9
Hence, the other root of the quadratic equation 2x²-3x+p = 0 is -3/2 and the value of p is -9.
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