if one root of the quadratic equation is 3+2√5/4 then what will be the other root?
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We know in a quadratic with rational coefficients irrational roots occur in conjugate pairs).
Since equation has rational coefficients, the other root is 3 - 2√3
Now, the sum of the roots of the given equation S = (3 - 2√3) + (3 + 2√3) = 6
Product of the roots, P = (3 - 2√3)(3 + 2√3) = -3
Hence, the required equation is x^2-6x-3=0
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