Math, asked by baqaabbaszaidi71, 1 year ago

if one root of the quadratic equation kx^2-5x+2=0 is 4 times the other find k?

Answers

Answered by Kartiksaiv
22

Answer:

k = 2

Step-by-step explanation:

Let the roots of the equation be A and B respectively.

Given: A = 4B

If the equation can be represented as the following

ax^2 + bx + c =0

where a = k

b= -5 & c=2

the sum of the roots is given by -b/a

which is 5/k= A + B=> 5/k = 5B .......(1)

Also, product of roots = c/a

2/k= A(B) => 2/k = 4B^2......(2)

From equation (1) we get k = 1/B

Putting value of k in equation (2), we get

2B = 4B^2

B = 1/2

Hence k =2

Hope this helps you...

Please mark as the brainliest answer...

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Just for cross checking the roots of the equation come out to be 1 and 4

which is the condition of the question...

Answered by Lalitpawar31
0

Answer:

k=2 is the answer of this question

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