if one root of the quadratic equation x^2-4x+1=0 is (2+root3) then the other root is .........
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Answer:
To find another zero of the polynamial x
2
−4x+1 , if one of them will be (2+
3
)
let consider two zeros α,β
α=2+
3
(given)
α+β=−
a
b
α+β=
1
−(−4)
(x
2
−4x+1comparingwithgenaralequationax
2
+bx+c,thena=1,b=−4,c=1)
α+β=4
fromequation(1)&(2)
α+β=4
2+
3
+β=4
β=4−(2+
3
)
β=4−2−
3
β=2−
3
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