If one root of the quadratic equation x square -11x+k=0 is 9 find the value of k
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putting value of x =9
81 - 11× 9 + k=0
81 - 99 + k=0
k= 18
81 - 11× 9 + k=0
81 - 99 + k=0
k= 18
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Answer:
Step-by-step explanation:
let the other root be y
therefore two roots will be 9 and y
as the roots sum should be equal to - b/a
therefore 9 + y= -(-11)/1
therefore y = 2
and also the product of roots is equal to c/a
therefore (9)(2) = k/1
therefore k = 18
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