if the 5th term of an ap is three times of the first term prove that 7th term is twice the third term
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proved..................
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Answer:
a + 4d = 3a
4d = 2a
a= 2d ....(I)
now,
T7 = a + 6d }
= 8d }. from (I)
also }
T3 = a + 2d }
= 4d
hence proved
t7= 2(t3)
Step-by-step explanation:
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