if one root of the quadratic equations 2x+kx-6=0is 2 the value of k is
Answers
Answered by
4
Answer:
k=1
Step-by-step explanation:
P(x) = 2x + kx- 6=0
One root is 2
P(2) = 2×2 + 2K -6 =0
= 4-6+2k =0
= 2k = 2
= K = 1
Answered by
1
Answer:
-1
Step-by-step explanation:
Let the roots be α and β
αβ= -6/2
2β=-3
β= -1.5
α+β= -k/2
2-1.5 = -k/2
k = - 1
2x² - 1x - 6 = 0
2x² -4x +3x -6 =0
2x(x-2)+3(x-2) =0
(x-2)(2x+3) = 0
x=2 or -1.5
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