Question

If one root of x^2-5x(6+k)=0 is zero,then what is value of k

Answer 1

Answer: -6

Step-by-step explanation:

0 ^ 2 - 5*0*(6 + k) = 0

0 - 0(6 + k) = 0

Looking at possible solutions, we find that:

0 - 0 must be = 0

Therefore 6 + k = 0

k = -6

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Answer 2

Answer:

Hope my answer helps you mate :-)

Step-by-step explanation:

If one root of equation above = 0

Put it in place of x in the equation as for its value whole equation will be 0

0 - 0(k+6)=0

0×(k+6)=0

0=0,k+6=0

k=-6

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