Question

If one root of x^2 + px +12 = 0is 4, while the equation x^2 + px + q =0
has equal roots, then the value of q is
(a) 49/4
(b) 4/49
(c) 4
(d) ¼

Answer 1

one root is 4
put x= 4 in x^2 + px +12 = 0
16 + 4p + 12 =0
p = -7

x^2 + px + q = 0 has equal roots
so Discriminant = 0
p^2 - 4q = 0
49 = 4q

q= 49/4

Answer 2

$\huge\pink{ ⛄ Answer ⛄ }$

Your answer is

( a ) 49/4

Hope it will help you